# Line slope calculator 4x+7y=64

**Straight line given by points A[2; 8] and B[9; 4]**

## Calculation:

**Slope-intercept form of line:**y = -0.5714x+9.1429

**Canonical form of the line equation:**4x+7y-64 = 0

**Parametric form of the line equation:**

x = 7t+2

y = -4t+8 ; t ∈ R

**Slope:**m = -0.5714

**Slope angle of line: φ =**-29°44'42″ = -0.5191 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 9.1429

**Distance line from the origin:**d

_{0}= 7.9382

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(7; -4)

**Normal vector: n =**(4; 7)

**Midpoint of the segment AB: M =**[5.5; 6]

**Perpendicular Bisector equation:**7x-4y-14.5 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (9; 4) ; |OB| = 9.8489**

**Scalar product OA .OB = 50**

**Angle ∠ AOB = 52°5″ = 0.9076 rad**