# Line slope calculator 5x+4y=45

**Straight line given by points A[1; 10] and B[5; 5]**

## Calculation:

**Slope-intercept form of line:**y = -1.25x+11.25

**Canonical form of the line equation:**5x+4y-45 = 0

**Parametric form of the line equation:**

x = 4t+1

y = -5t+10 ; t ∈ R

**Slope:**m = -1.25

**Slope angle of line: φ =**-51°20'25″ = -0.8961 rad

**X intercept:**x

_{0}= 9

**Y intercept:**y

_{0}= q = 11.25

**Distance line from the origin:**d

_{0}= 7.0278

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; -5)

**Normal vector: n =**(5; 4)

**Midpoint of the segment AB: M =**[3; 7.5]

**Perpendicular Bisector equation:**4x-5y+25.5 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (5; 5) ; |OB| = 7.0711**

**Scalar product OA .OB = 55**

**Angle ∠ AOB = 39°17'22″ = 0.6857 rad**